For a cetain gas, 20.0 mg exerts a pressure of 24.7 Torr in a 500 cm3 vessel at 25 degrees Celsius. Find the molar mass.
solution
Mx = 20.0 mg Px= 24.7 torr Vx= 500 cm3 T= 25C+ 273K= 298 K
M=?
n= PV/RT= 24.7 torr (0.500L)/ 62.364 L torr /K.mol (298K) = 0.000665 mol
n=m/M= .0200 g/0.000665 mol= 30.0 g/mol
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