What is the pressure exerted by 24 .0 g of carbon dioxide gas in a 25 dm3 container at 0 degrees Celsius, Express the pressure in Pa and bar.
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Answer
PCO2=? Pa & bar
VCO2= 25 dm3
mCO2= 24.0 g
T= 273K
R= 8.3145 L.bar/molK
nCO2= 24.0 g/ 44 g/mol = 0.545 mol
PCO2= nRT/V= 0-545
mol(8.3145 X 10-2
L bar/
molK) (273
K)/ 25
L= .495 bar
49.5 bar ( 1.0 x 10 5 Pa/bar)= 4.95 x 104 Pa
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